Clocks and Calendar - Clock Problem
Clocks and Calendar - Clock Problem
Clocks and Calendar - Clock Problem: This concept revolves around the calculation of the angular distance traversed by the different hand of the clock. The different hands of the clock move with different speed.The hour hand takes 12 hours to traverse an angle of 360 degree, and the minute hand completes one rotation in one hour i.e. it covers in 1 hour .
Speed of minute hand = in 1 hour ( 60 min )
= per minute
Speed of hour hand = in 12 hours
= in 1 hour ( 60 min )
=
As they are moving in the same direction
So, the relative speed of minute hand over hour hand will be difference of their speeds
Illustration: At what time immediately after 2 o' clock, do the hands of clocks coincide?
A. 10 minutes 11 seconds. B. 10 minutes 10 seconds. C. 10 minutes 55 seconds. D. 9 minutes 55 seconds.
Answer: C
Solution: At 2 o'clock, the hands of the clock are apart.
The minute hand covers this at a speed of
per minute.
To cover , time required = 1 min
TO cover , time required
minutes
If we convert minutes to seconds, it is equal to
= 55 seconds (approx)
So, the answer is 10 minutes 55 seconds.
At what time between 5 and 6 are the hands of a clock coincident? | |||
| Right Option : D | |||
| View Explanation | |||
At what time between 5.30 and 6 o'clock will the hands of a clock be at right angle? | |||
| Right Option : B | |||
| View Explanation | |||
At what time immediately after 7 o' clock, do the hands of clocks coincide? | |||
| Right Option : D | |||
| View Explanation | |||
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